19x^2+22x-41=0

Solution for 19x^2+22x-41=0 equation:

Simplifying
19x2 + 22x + -41 = 0

Reorder the terms:
-41 + 22x + 19x2 = 0

Solving
-41 + 22x + 19x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-41 + -19x)(1 + -1x) = 0

Subproblem 1
Set the factor '(-41 + -19x)' equal to zero and attempt to solve:

Simplifying
-41 + -19x = 0

Solving
-41 + -19x = 0

Move all terms containing x to the left, all other terms to the right.

Add '41' to each side of the equation.
-41 + 41 + -19x = 0 + 41

Combine like terms: -41 + 41 = 0
0 + -19x = 0 + 41
-19x = 0 + 41

Combine like terms: 0 + 41 = 41
-19x = 41

Divide each side by '-19'.
x = -2.157894737

Simplifying
x = -2.157894737
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {-2.157894737, 1}